(Tutorial) Python String Contains – DataCamp
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If you’re seeking to discover or change objects in a string, Python has a number of built-in strategies that may show you how to search a goal string for a specified substring.
.discover()
Methodology
Syntax
string.discover(substring, begin, finish)
Be aware: begin
and finish
are non-obligatory arguments.
From the above syntax, you may observe that the .discover()
technique takes the specified substring because the necessary argument. You may specify the opposite two arguments: an inclusive beginning place and an unique ending place.
Substring Search
Within the instance code, you seek for Waldo
within the string The place's Waldo?
. The .discover()
technique returns the bottom index within the string the place it may possibly discover the substring, on this case, eight.
my_string = "The place's Waldo?"
my_string.discover("Waldo")
8
In the event you seek for Wenda
, it returns -1
for the reason that substring shouldn’t be discovered.
my_string.discover("Wenda")
-1
Let’s have a look at if you could find Waldo
between characters zero and 5. Within the code, you specify the beginning place zero and ending place as six, since this place shouldn’t be inclusive.
my_string = "The place's Waldo?"
my_string.discover("Waldo", 0, 6)
-1
The .discover()
technique doesn’t discover the substring and returns -1
, as proven above.
.index()
Methodology
Syntax
string.index(substring, begin, finish)
Be aware: begin
and finish
are non-obligatory arguments.
From the above syntax, you may observe that the .index()
technique takes the specified substring as a compulsory argument. It could actually take non-obligatory beginning and ending positions as nicely.
Substring Search
Within the instance, we search once more for Waldo utilizing .index()
.
my_string = "The place's Waldo?"
my_string.index("Waldo")
8
We get eight once more. Once we search for a substring that’s not there, we have now a distinction.
my_string.index("Wenda")
File "<stdin>", line 1, in <module>
ValueError: substring not discovered
The .index()
technique raises an exception, as we will see within the output. We are able to deal with this utilizing the attempt besides block.
my_string = "The place's Waldo?"
attempt:
my_string.index("Wenda")
besides ValueError:
print("Not discovered")
Above, you may observe the syntax. The attempt half will take a look at the given code. If any error seems, the besides half will likely be executed, acquiring the next output because of this.
"Not discovered"
.rely()
Methodology
The .rely()
technique searches for a specified substring within the goal string. It returns the variety of non-overlapping occurrences. In easy phrases, what number of instances the substring is current within the string.
Syntax
The syntax of .rely()
is similar to the opposite strategies, as we will observe.
string.rely(substring, begin, finish)
Be aware: begin
and finish
are non-obligatory arguments.
Substring Rely
Within the instance, we use the .rely()
technique to get what number of instances fruit seems.
my_string = "What number of fruits do you have got in your fruit basket?"
my_string.rely("fruit")
2
Within the output, we see that’s is 2.
We are able to then restrict the occurrences of fruit between character zero and fifteen of the string, as we will observe within the code beneath.
my_string.rely("fruit", 0, 16)
1
The tactic will return 1
. Do not forget that the beginning place is inclusive, however the ending shouldn’t be.
.change
Methodology
Generally you’ll want to change occurrences of a substring with a brand new substring. On this case, Python gives us with the .change
technique.
Syntax
string.change(previous, new, rely)
Be aware: rely
is an non-obligatory argument.
As we see within the syntax above, it takes three arguments: the substring being changed, the brand new string to exchange it, and an non-obligatory quantity that signifies what number of occurrences to exchange.
Changing a Substring
Within the instance code, we change the substring home with automotive.
my_string = "The pink home is between the blue home and the previous home"
print(my_string.change("home", "automotive"))
The pink automotive is between the blue automotive and the previous automotive
The tactic will return a replica with all home substrings changed.
Changing a Particular Variety of Occurrences
On this instance, we specified that we solely need 2 of the occurrences to get replaced.
print(my_string.change("home", "automotive", 2))
The pink automotive is between the blue automotive and the previous home
Within the output, we see that the strategy returns a replica of the string with the primary two occurrences of home changed by automotive.
Interactive Instance
Within the beneath instance, you’ll:
- Discover if the substring
actor
happens between the characters with index37
and41
inclusive. If it isn’t detected, print the assertionPhrase not discovered
. - Change
actor actor
with the substringactor
ifactor
happens solely two repeated instances. - Change
actor actor actor
with the substring actor ifactor
seems three repeated instances.
for film in films:
# Discover if actor occurrs between 37 and 41 inclusive
if film.discover("actor", 37, 42) == -1:
print("Phrase not discovered")
# Rely occurrences and change two by one
elif film.rely("actor") == 2:
print(film.change("actor actor", "actor"))
else:
# Change three occurrences by one
print(film.change("actor actor actor", "actor"))
Once we run the above code, it produces the next consequence:
Phrase not discovered
I imagine you I at all times mentioned that the actor is wonderful in each film he has performed
it is astonishing how scary the actor norton seems with a shaved head and a swastika on his chest.
To be taught extra about discovering and changing strings, please see this video from our course, Regular Expressions in Python.
This content material is taken from DataCamp’s Regular Expressions in Python course by Maria Eugenia Inzaugarat.
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